-
JonasBrrt, today at 12:33 am CEST
-
JJepsa96, yesterday at 09:26 pm CEST
-
JonasBrrt, yesterday at 06:33 pm CEST
-
Max1989, today at 12:19 am CEST
-
Maximale, today at 12:08 am CEST
-
Touchy123, yesterday at 11:40 pm CEST
-
Olli_Eule, yesterday at 11:37 pm CEST
-
Donnie, yesterday at 11:07 pm CEST
-
merkator88, yesterday at 10:53 pm CEST
-
DerLorax, yesterday at 09:49 pm CEST
-
JJepsa96, yesterday at 09:37 pm CEST
-
JJepsa96, yesterday at 09:34 pm CEST
-
JJepsa96, yesterday at 09:29 pm CEST
-
HollandMan, yesterday at 08:36 pm CEST
-
Olli_Eule, yesterday at 08:25 pm CEST
-
Angelina12, yesterday at 07:53 pm CEST
-
BigAl87, yesterday at 07:14 pm CEST
-
Olli_Eule, yesterday at 07:02 pm CEST
-
Deadspin, yesterday at 05:39 pm CEST
-
Kinglol, yesterday at 05:08 pm CEST
-
moody, yesterday at 02:33 pm CEST
-
Langhans_innen, yesterday at 12:29 pm CEST
-
JackieNL, yesterday at 11:32 am CEST
-
WithoutWings, on 3rd Apr. 2025 at 07:57 pm CEST
-
agnesaislami, on 3rd Apr. 2025 at 07:51 pm CEST
-
Pneumatic, on 3rd Apr. 2025 at 03:16 pm CEST
play the numbers that belong to the third third and they are on the board.
Nobody has liked this post so far
3x37 =111 if you throw the ball 111 times then the numbers do not come three times as the statistics would say, but
the first third does not come once 0x
the second third comes once or twice 1-2x
the third third comes three times-seven times 3-7x
this means you always have to play the numbers that belong to the third third and these are on the board.
Does anyone know this strategy and have they had any experience with it or even won?
This post has been translated automatically
play the numbers that belong to the third third and they are on the board.
Liked this post:
Dr-Strange,
Hanshanshans,
Malganes
This post has been translated automatically