Maggi89 wrote on 31.01.2025 at 22:14:
For me the function is not with Jackpot
Looked again marke must be at Jackpot because at BingBong I can choose it. I have 3 correct and the support answer zero
I also had 3 correct and the wrong favorite brand set.
Therefore nothing
I really feel like I've been taken for a ride
Hahahaha I can't take anymore, their marketing department I would fire immediately hahaha had to laugh so hard, and what kind of features are those supposed to be? Cool cool cool and symbols you've never seen before 😂😂😂😂
Do you want to laugh? All of a sudden it's not marketing anymore but my profile would be unverified. Boy what? I replied but it's been a pain in the ass I sent scren in the attachments that brand marketing was correct. And that my profile is verified. I added that there have been similar problems before and asked them to refer me to the technical department, whose competence is hopefully higher than a toast. I then took the whole thing and contacted support again. I wouldn't care about the whole thing, but I'm simply in the right and that's a fact.
And if my account wasn't verified, I wouldn't be able to take part in any promo - that's as much a fact as the ámen in the church. So promo without depositor and it is not the first time that I had 3 right. I have written everything to the cart
I need a probability calculation for the following situation, purely theoretically.
We have 25 doors to choose from
11 of these doors contain the term "win". The other 14 contain the term "Loose".
We are allowed to select 4 doors, the other 21 doors remain closed.
What is the mathematical chance of all 4 possible outcomes?
0/4 wins, 1/4 wins, 2/4 wins, 3/4 wins, 4/4 wins
If you have opened 1 door and it had a "Loose" in it, for example, the probability for the others changes.
Exactly, even if we had a "win" in the 1st attempt.
The basic probability 11/25 is 44 %, but the classic 44 % * 44 % * 44 % * 44 % = 3 % chance for 4/4 wins can't apply here, can it?
And what is the probability for 3/4 and 2/4, for example?
Butterbrezel wrote on 02.02.2025 at 14:20: Is this a mathematician?
I need a probability calculation for the following situation, purely theoretically.
We have 25 doors to choose from
11 of these doors contain the term "win". The other 14 contain the term "Loose".
We are allowed to select 4 doors, the other 21 doors remain closed.
What is the mathematical chance of all 4 possible outcomes?
0/4 wins, 1/4 wins, 2/4 wins, 3/4 wins, 4/4 wins
If you have opened 1 door and it had a "Loose" in it, for example, the probability for the others changes.
Exactly, even if we had a "win" in the 1st attempt.
The basic probability 11/25 is 44 %, but the classic 44 % * 44 % * 44 % * 44 % = 3 % chance for 4/4 wins can't apply here, can it?
And what is the probability for 3/4 and 2/4, for example?
Please help from a mathematician
Not a mathematician, but I took statistics at university and stochastics in high school (basically the same subject).
But yes, your assumption should be correct. I don't see anything wrong with it. Why do you have concerns? You can ask safe chatgtp or something
Edit: I asked for you, here's the result:
But I don't understand why it's 31% at 1:4. It's actually 11/25 and at 0/4 it's 14/25 which is certainly not 8%
Ahhh I see... okay. the 44% (i.e. 11/25) is only the case if you open the doors one at a time. If you have to open all 4 at once, then you have to use a formula for this and the probabilities change accordingly.
I just paid out €100 at JackpotPiraten from no deposit. Please don't Deposit the wager was pure luck. It went like shit. 12.30 was my win from free spins.
Zockerbernd wrote on 03.02.2025 at 15:06: I just spent €100 on JackpotPiraten from no deposit. Please do not Deposit the wager was pure luck. It went like shit. 12.30 was my win from free spins.
you could have just written that you won €100 gambling whether you like it or not, it was indirect advertising...when rappers are dissed, that's advertising too...
Chatterbox
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I also had 3 correct and the wrong favorite brand set.
Therefore nothing
I really feel like I've been taken for a ride
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Chatterbox
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Chatterbox
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Do you want to laugh? All of a sudden it's not marketing anymore but my profile would be unverified. Boy what? I replied but it's been a pain in the ass I sent scren in the attachments that brand marketing was correct. And that my profile is verified. I added that there have been similar problems before and asked them to refer me to the technical department, whose competence is hopefully higher than a toast. I then took the whole thing and contacted support again. I wouldn't care about the whole thing, but I'm simply in the right and that's a fact.
And if my account wasn't verified, I wouldn't be able to take part in any promo - that's as much a fact as the ámen in the church. So promo without depositor and it is not the first time that I had 3 right. I have written everything to the cart
This post has been translated automatically
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Liked this post:
gamble1,
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I need a probability calculation for the following situation, purely theoretically.
We have 25 doors to choose from
11 of these doors contain the term "win". The other 14 contain the term "Loose".
We are allowed to select 4 doors, the other 21 doors remain closed.
What is the mathematical chance of all 4 possible outcomes?
0/4 wins, 1/4 wins, 2/4 wins, 3/4 wins, 4/4 wins
If you have opened 1 door and it had a "Loose" in it, for example, the probability for the others changes.
Exactly, even if we had a "win" in the 1st attempt.
The basic probability 11/25 is 44 %, but the classic 44 % * 44 % * 44 % * 44 % = 3 % chance for 4/4 wins can't apply here, can it?
And what is the probability for 3/4 and 2/4, for example?
Please help from a mathematician
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Chatterbox
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Butterbrezel,
gamble1,
Langhans_innen,
Saphira
Not a mathematician, but I took statistics at university and stochastics in high school (basically the same subject).
But yes, your assumption should be correct. I don't see anything wrong with it. Why do you have concerns? You can ask safe chatgtp or something
Edit: I asked for you, here's the result:
But I don't understand why it's 31% at 1:4. It's actually 11/25 and at 0/4 it's 14/25 which is certainly not 8%
Ahhh I see... okay. the 44% (i.e. 11/25) is only the case if you open the doors one at a time. If you have to open all 4 at once, then you have to use a formula for this and the probabilities change accordingly.
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I didn't think of the simplest solution, asking ChatGPT. Thank you
Question thus answered.
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you could have just written that you won €100 gambling whether you like it or not, it was indirect advertising...when rappers are dissed, that's advertising too...
🙃🙃🙃
The pirates will get it back anyway 😀
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Yes, it's still going on now, I'm curious to see if they get it under control until the cup game.
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